The correct option is A →a|→a|+→b|→b|+→c|→c|
Let →α=→a|→a|+→b|→b|+→c|→c|
Since →a,→b and →c are mutually perpendicular vectors, if →α makes angles θ,ϕ,Ψ with →a,→b and →c, respectively, then
→α⋅→a=→a⋅→a|→a|
or |→α|⋅|→a|cosθ=|→a|
or cosθ=1|→α|
Similarly, cosϕ=1|→α|,cosΨ=1|→α|
∴θ=ϕ=Ψ