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Question

If a,b and c are three mutually perpendicular vectors, then the vector which is equally inclined to these vectors is

A
a+b+c
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B
a|a|+b|b|+c|c|
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C
a|a|2+b|b|2+c|c|2
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D
|a|a|b|b+|c|c
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Solution

The correct option is A a|a|+b|b|+c|c|
Let α=a|a|+b|b|+c|c|
Since a,b and c are mutually perpendicular vectors, if α makes angles θ,ϕ,Ψ with a,b and c, respectively, then
αa=aa|a|
or |α||a|cosθ=|a|
or cosθ=1|α|
Similarly, cosϕ=1|α|,cosΨ=1|α|
θ=ϕ=Ψ

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