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Question

If a,b and c are three non-coplanar vectors, then (a+b+c)[(a+b)×(a+c)] equals


A

0

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B

[abc]

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C

2.[abc]

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D

[abc]

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Solution

The correct option is D

[abc]


(a+b+c).[(a+b)×(a+c)]=(a+b+c).[a×a+a×c+b×a+b×c]={a.(a×c)+a.(b×a)+a.(b×c)}+{b.(a×c)+b.(b×a)+b.(b×c)}+{c.(a×c)+c.(b×a)+c.(b×c)}[abc]+[bac]+[cba][abc]


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