If →a,→b and →c are three unit vectors such that →a+→b+→c is also a unit vector and θ1,θ2 and θ3 are the angles between the vectors →a,→b;→b,→c and →c,→a, then
A
All are acture angles
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B
All are right angles
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C
At least one is obtuse angle
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D
Exactly one is obtuse angle
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Solution
The correct option is C At least one is obtuse angle Since ∣∣→a+→b+→c∣∣=1⇒(→a+→b+→c).(→a+→b+→c)=1
⇒1+1+1+2(→a.→b+→b.→c+→c.→a)=1
(→a.→b+→b.→c+→c.→a)=−1
cosθ1+cosθ2+cosθ3=−1
So atleast one of these 3 values cosθ must be negative.