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Subtraction of a Vector

If |A⃗-B⃗|=|A...

Question

If $| \to A - \to B | = | \to A | = | \to B |,$ the angle between \( \vec{A}\) and $\to B$

A

$60^{\circ}$

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B

$0^{\circ}$

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C

$120^{\circ}$

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D

$90^{\circ}$

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Solution

The correct option is A
$60^{\circ}$

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Similar questions

∣ ∣ \to A - \to B ∣ ∣ = ∣ ∣ \to A ∣ ∣ = ∣ ∣ \to B ∣ ∣

, the angle between

\to A

\to B

| \to a + \to b | < | \to b - \to a |

then angle between

\to a

\to b

| \to A + \to B | = | \to A | = | \to B |

, then the angle between

\to A

\to B

| \to A | = | \to B |

, then what is the angle between

\to A + \to B

\to A - \to B

:

\to a

\to b

are unequal vectors such that

(\to a - \to b) \times [(\to b + \to a) \times (2 \to a + \to b)] = \to a + \to b

, then the angle

θ

\to a

\to b

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