If a- - b- - c- are any three vectors such that a- -b- -c- - a- - b- -c- - 0 then a-b- -c- is

The correct option is B (a⃗.b⃗).c⃗ .(a̅+b̅)·c̅=0⇒a̅·c̅+b̅·c̅=0 (a̅ b̅)·c̅=0⇒a̅·c̅ b̅·c̅=0] ⇒a̅·c̅=0 b̅·c̅=0 (a̅×b̅)×c̅=(a̅·c̅)b̅ ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Vectors and Its Types

If a⃗ , b⃗ ...

Question

If $\to a, \to b, \to c$ are any three vectors such that $(\to a + \to b) \cdot \to c = (\to a - \to b) \cdot \to c = 0$ then $(\to a \times \to b) \times \to c$ is

\to 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\to a . \to b) . \to c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- (\to a . \to b) . \to c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

\to a \cdot \to b + \to b \cdot \to c + \to c \cdot \to a =

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

\to a \cdot \to b + \to b \cdot \to c + \to c \cdot \to a

\to A, \to B, \to C

\to A

\to B

\to C

\to B

\to C

0

\to a, \to b, \to c

{\to b}_{1} = \to b - \frac{\to b \cdot \to a}{| \to a |^{2}} \to a,

{\to b}_{2} = \to b + \frac{\to b \cdot \to a}{| \to a |^{2}} \to a

{\to c}_{1} = \to c - \frac{\to c \cdot \to a}{| \to a |^{2}} \to a + \frac{\to b \cdot \to c}{| \to c |^{2}} {\to b}_{1},

{\to c}_{2} = \to c - \frac{\to c \cdot \to a}{| \to a |^{2}} \to a - \frac{{\to b}_{1} \cdot \to c}{| {\to b}_{1} |^{2}} {\to b}_{1},

{\to c}_{3} = \to c - \frac{\to c \cdot \to a}{| \to c |^{2}} \to a + \frac{\to b \cdot \to c}{| \to c |^{2}} {\to b}_{1}, {\to c}_{4} = \to c - \frac{\to c \cdot \to a}{| \to c |^{2}} \to a - \frac{\to b \cdot \to c}{| \to b |^{2}} {\to b}_{1}

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

| \to a \times \to b | + | \to b \times \to c | + | \to c \times \to a | =

Join BYJU'S Learning Program