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Question

If a,b,c are non coplanar and [abc]=47, then [2ab,2bc,2ca] is

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Solution

[2ab,2bc,2ca]=(2ab)[(2bc)(2ca)]

=(2ab)[4b.c2b.ac.2c+c.a]

=8a.(b.c)2a(2b.c)+2a(c.a)

=8a.(b.c)2a(2b.c)+2a(c.a)b.(4b.c)+b.(2b.c)b.(c.a)

As given a,b,c are non coplanar,

=8[a.b.c]0+00+0[a.b.c]

Put value of [a.b.c]=47 as given

=8.4747

=47(81)

=4


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