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Question

If a,b,c are non coplanar non zero vectors, then the value of (a×b)×(a×c)+(b×c)×(b×a)+(c×a)×(c×b) is

A
[abc]2(a+b+c)
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B
[abc](a+b+c)
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C
0
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D
None of these
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Solution

The correct option is D [abc](a+b+c)
(a×b)×(a×c)+(b×c)×(b×a)+(c×a)×(c×b)

=b(a(a×c))a(b(a×c))+c(b(b×a))b(c(b×a))+
a(c(c×b))c(a(c×b))
=b[aac]a[bac]+c[bba]b[cba]+
a[ccb]c[acb]
we khow that ,
(1)[aab]=0 and
(2)[abc]=[cab]=[bca]=[bac]=
[cba]=[acb]

Hence by using the concepts of (1)& (2)

eqn. can be written as,

=b0+a[abc]+c0+b[abc]+a0+c[abc]
=[abc](a+b+c)

Hence, (B) is the correct answer.



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