If a- b- c- are non-coplanar then - a-2b- b-2c- c-2a- - a- b- c- -

The correct option is C 9 [ #160;a⃗+2b⃗ amp; b⃗+2c⃗ amp; c⃗+2a⃗ #160; ] = [ 1 amp; 2 amp; 0; 0 amp; 1 amp; 2; 2 amp; 0 amp; ...

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Summation of Determinant

If a⃗, b⃗...

Question

If $\to a$ , $\to b$ , $\to c$ are non-coplanar then $\frac{[\begin{matrix} \to a + 2 \to b & \to b + 2 \to c & \to c + 2 \to a \end{matrix}]}{[\begin{matrix} \to a & \to b & \to c \end{matrix}]}$

2

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Solution

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Similar questions

\to a, \to b, \to c

[\to a \to b \to c] = \frac{4}{7}

[2 \to a - \to b, 2 \to b - \to c, 2 \to c - \to a]

\to a, \to b, \to c

\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}

\to q = \frac{\to c \times \to a}{[\to a \to b \to c]}

\to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(2 \to a + 3 \to b + 4 \to c) . \to p + (2 \to b + 3 \to c + 4 \to a) . \to q +

(2 \to c + 3 \to a + 4 \to b) . \to r =

\to a, \to b, \to c

_{1} = \to a - \to b + \to c,_{2} = \to b + \to c - \to a

_{3} = \to c + \to a - \to b, \to r = 2 \to a - 2 \to b + 4 \to c

\to r = x_{1}_{1} + x_{2}_{2} + x_{3}_{3}

\to a, \to b, \to c

2 \to a + \to b, \to a + 2 \to b + \to c, 4 \to a - 2 \to b - \to c

3 \to a + 4 \to b - 5 \to c

\to a, \to b, \to c

\to b \times \to c = \to a

\to a \times \to b = \to c

\to c \times \to a = \to b

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