If →a,→b,→c are non-coplanar unit vectors such that →a×(→b×→c)=→b+→c√2, then the angle between →a and →b is
A
3π4
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B
π4
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C
π2
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D
π
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Solution
The correct option is D3π4 →a×(→b×→c) =→b(→a.→c)−→c→a.→b) =→b√2+→c√2 Comparing coefficients, we get →a.→c=1√2 and →a.→b=−1√2 If θ is the angle between →a and →b, then cosθ=−12 Hence angle between →a and →b is 3π4