If →a,→b,→c are non-coplanar unit vectors such that →a×(→b×→c)=(→b+→c)√2, then the angle between →a and →b is
A
3π4
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B
π4
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C
π2
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D
π
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Solution
The correct option is A3π4 Since, →a×(→b×→c)=→b+→c√2 ⇒(→a.→c)→b−(→a.→b)→c=1√2→b+1√2→c On equating the coefficient of →c, we get →a.→b=−1√2⇒|→a||→b|cosθ=−1√2∴cosθ=−1√2⇒θ=3π4