If a-b- c- are non-coplanar vectors and - is a real number- then -a-b-2b-c-a-b-c-b- for

Let $\to a, \to b, \to c$ be three vectors such that $| \to a | = | \to c | = 1; | \to b | = 4$ and $| \to b \times \to c | = \sqrt{15}$ . If $\to b - 2 \to c = λ \to a$ then a value of $λ$ is

If $\to a, \to b, \to c$ are non-coplanar vectors and $\to d = λ \to a + μ \to b + ν \to c,$ then $λ$ equal to

Q. If

\to a, \to b, \to c

are non-coplanar vectors and

λ

is a real number, then the vectors

\to a + 2 \to b + 3 \to c, λ \to b + 4 \to c

and

(2 λ - 1) \to c

are non-coplanar for

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If →a,→b, →c are non-coplanar vectors and λ is a real number, then [λ(→a+→b)λ2→bλ→c]=[→a→b+→c→b] for

The correct option is C No vlaue of λλ(→a+→b).(λ3→b×→c)=λ4(→a→b→c) ----(1)→a.((→b+→c)×→b)=→a.→c×→b ----(2)equal (1) & (2)λ4=−1So λ can't be real.

If $\to a, \to b, \to c$ are non-coplanar vectors and $λ$ is a real number, then $[λ (\to a + \to b) λ^{2} \to b λ \to c] = [\to a \to b + \to c \to b]$ for

The correct option is C No vlaue of $λ$
$λ (\to a + \to b) . (λ^{3} \to b \times \to c) = λ^{4} (\to a \to b \to c)$ ----(1)
$\to a . ((\to b + \to c) \times \to b) = \to a . \to c \times \to b$ ----(2)
equal (1) & (2)
$λ^{4} = - 1$
So $λ$ can't be real.