If a- b- c- are non coplanar vectors such that b-c- - a- c-a- - b- and a-b- - c- then

The correct options are A |a⃗| = 1 B |b⃗| = 1 C |c⃗| = 1 D |a⃗| + |b⃗| + |c⃗| = 3 ...

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Test for Coplanarity

If a⃗, b⃗, ...

Question

If $\to a, \to b, \to c$ are non coplanar vectors such that $\to b \times \to c = \to a, \to c \times \to a = \to b$ and $\to a \times \to b = \to c$ , then

| \to a | = 1

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| \to b | = 1

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| \to c | = 1

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| \to a | + | \to b | + | \to c | = 3

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Solution

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Similar questions

\to a, \to b, \to c

\to b \times \to c = \to a

\to a \times \to b = \to c

\to c \times \to a = \to b

\to a, \to b, \to c

(\to a \times \to b) \times (\to a \times \to c) + (\to b \times \to c) \times (\to b \times \to a) + (\to c \times \to a) \times (\to c \times \to b)

\to A, \to B

\to C

(\to A + \to B + \to C) \cdot [(\to A + \to B \times (\to A + \to C)]

If $\to a, \to b$ and $\to c$ are three non-coplanar vectors, then $(\to a + \to b + \to c) \cdot [(\to a + \to b) \times (\to a + \to c)]$ equals

\to A, \to B

\to C

(\to A + \to B + \to C) . [(\to A + \to B) \times (\to A + \to C)]

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