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Question

If a,b,c are three non coplanar non zero vectors, then (aa)b×c+(ab)c×a+(a.c)a×b is equal to

A
[b c a]a
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B
[c a b]b
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C
[a b c]c
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D
None of these
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Solution

The correct option is A [b c a]a
Let (a.a)b×c+(ab)c×a+(ac)a×b=x
Now
xa=(aa)[abc]
xb=(ab)[abc]
xc=(a.c)[abc]
Adding the three equations, we get
x(a+b+c)=a(a+b+c)[abc]
x=[a b c]a[bca]a

Hence, option A.

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