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Question

If a,b,c are three non coplanar vectors represented by concurrent edges of a parallelepiped of volume 4 then
(a+b).(b×c)+(b+c).(c×a)+(c+a).(a×b) is equal to

A
12
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B
4
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C
±12
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D
0
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Solution

The correct option is C ±12
[abc]=±4 from the definition of volume of a parallelopipe

Thus, (a+b).(b×c)+(b+c)(c×a)+(c+a)(a×b)=

[abc]+0+[bca]+0+[cab]+0

=3[abc]

=±12

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