If a- b- c- are three unit vectors such that a- - b- - c- - 0- where 0- is null vector- then a- - b- - b- c- - c- - a- is

The correct option is C 3/2 We have a⃗ + b⃗ + c⃗ = 0⃗ ∴ |a⃗ + b⃗ + c⃗| = 0 ⇒ |a̅ + b̅ + c̅|^2 = 0 ⇒ |a⃗|^2 + |b⃗|^2 + |c⃗|^2 + 2 (a⃗. b⃗ + ...

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Test for Collinearity of Vectors

If a⃗, b⃗, ...

Question

If $\to a, \to b, \to c$ are three unit vectors such that $\to a + \to b + \to c = \to 0$ , where $\to 0$ is null vector, then $\to a . \to b + \to b . \to c + \to c . \to a$ is

- 3

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- 2

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\frac{3}{2}

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0

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\to a, \to b

\to c

\to a + 2 \to b + 2 \to c = \to 0

| \to a \times \to c |

\to a, \to b, \to c

\to a + \to b + \to c = 0

\to a . \to b + \to b . \to c + \to c . \to a

| \to a | = | \to b | = | \to c | = 1

\to a + \to b + \to c = \to 0

\to a . \to b + \to b . \to c + \to c . \to a = \frac{- 3}{2}

(\to p + \to q)^{2} = | \to p |^{2} + | \to q |^{2} + 2 \to p . \to q

\to a, \to b,

\to c

\to a + 2 \to b + 2 \to c = \to 0,

| \to a \times \to c |

\to a, \to b

\to c

\to a + 2 \to b + 2 \to c = \to 0

| \to a \times \to c |

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