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Question

If a,b,c are three vectors such that |a|=5,|b|=12 and |c|=13 and a+b+c=0

Find the value of a.b+b.c+c.a.

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Solution

Given that:
a+b+c=0 and |a|=5,|b|=12,|c|=13
Now,
|a+b+c|2=(a+b+c).(a+b+c) [|k|2=k.k]
0=|a|2+|b|2+|c|2+2(a.b+b.c+c.a)
0=52+(12)2+(13)2+2(a.b+b.c+c.a)
2(a.b+b.c+c.a)=(25+144+169)
2(a.b+b.c+c.a)=338
(a.b+b.c+c.a)=169



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