If a- - b- - c- are three vectors such that a-b- - c- - b-c- - a- - c-a- - b- then prove that - a- - - - b- - - - c- -

a⃗×b⃗=c⃗ c⃗.(a⃗×b⃗)=c⃗.c⃗ c⃗.(a⃗×b⃗)= | c⃗ |^2 ..... (1) b⃗×c⃗=a⃗ a⃗.(b⃗×c⃗)=a⃗.a⃗ a⃗.(b⃗×c⃗)= | a⃗ |^2 ..... (2) c⃗×a⃗=b⃗^⃗2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Multiplication with Vectors

If a⃗ , b⃗ ...

Question

If $\to a, \to b, \to c$ are three vectors such that $\to a \times \to b = \to c, \to b \times \to c = \to a, \to c \times \to a = \to b$ then prove that $| \to a | = | \to b | = | \to c |$

Open in App

Solution

Suggest Corrections

Similar questions

\to a, \to b, \to c

\to a, \to b, \to c

\to a \times \to b = \to b \times \to c = \to c \times \to a

[\to a \to b \to c] = 0.

\to A

\to B

\to C

| \to B | =

\to C |

[(\to A + \to B) \times (\to A + \to C)] \times (\to B \times \to C) . (\to B + \to C) = 0

\to a, \to b, \to c

\to a + \to b + \to c = \to 0,

\to a \times \to b = \to b \times \to c = \to c \times \to a,

[\to a \to b \to c] = 0.

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

| \to a \times \to b | + | \to b \times \to c | + | \to c \times \to a | =

\to a, \to b, \to c

\to b \times \to c = \to a, \to c \times \to a = \to b

\to a \times \to b = \to c

Join BYJU'S Learning Program