If →a,→b,→c are unit vectors such that →a is perpendicular to the →b and →c and angle between →b and →c is π3, then value of |→a+→b+→c| is
A
4
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B
2
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C
9
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D
3
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Solution
The correct option is C2 →a⋅→b=0→a⋅→c=0∣∣→a+→b+→c∣∣2=|a|2+|b|2+|c|2+2(→a⋅→b+→b⋅→c+→c⋅→a)=3+2→b⋅→c=3+2×1×1×12=4∣∣→a+→b+→c∣∣=2Hence,thecorrectoptionis(B)