If a-b-c- are unit vectors- then the maximum value of -2a- - 3b-2 - -2b- - 3c-2 - -2c- - 3a-2 is

The correct option is C 57 | a⃗ +b⃗ +c⃗ #160;| #160;^ 2 ≥ 0 ⇒ #160;3+2∑ #160;a⃗ .b⃗≥ 0 ⇒ 2∑ #160;a⃗ .b⃗≤ 3 Now, #160; |2a ...

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Multiplication with Vectors

If a⃗,b⃗,c⃗...

Question

If $\to a, \to b, \to c$ are unit vectors, then the maximum value of $| 2 \to a - 3 \to b |^{2} + | 2 \to b - 3 \to c |^{2} + | 2 \to c - 3 \to a |^{2}$ is

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\to a, \to b, \to c

\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}

\to q = \frac{\to c \times \to a}{[\to a \to b \to c]}

\to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(2 \to a + 3 \to b + 4 \to c) . \to p + (2 \to b + 3 \to c + 4 \to a) . \to q +

(2 \to c + 3 \to a + 4 \to b) . \to r =

2 \to a + 3 \to b - \to c, \to a - 2 \to b + 3 \to c, 3 \to a + 4 \to b - 2 \to c a n d \to a - 6 \to b + 6 \to c

\to a, \to b a n d \to c

\to a, \to b, \to c

{∣ ∣ \to a - 2 \to b ∣ ∣}^{2} + {∣ ∣ \to b - 2 \to c ∣ ∣}^{2} + {| \to c - 2 \to a |}^{2}

\to a + \to b - 2 \to c, \to a - 3 \to b + \to c

2 \to a - \to b - \to c

\to a, \to b, \to c

2 \to a + \to b, \to a + 2 \to b + \to c, 4 \to a - 2 \to b - \to c

3 \to a + 4 \to b - 5 \to c

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