If a- - b- - c- are unit vectors- then - a- - b- -2 - - b- - c- -2 - - c- - a- -2 does not exceed -

The correct option is A 9 E = | a⃗ b⃗|^2 + | b⃗ c⃗|^2 + | c⃗ a⃗|^2 2 (1+1+1) 2 ∑a⃗·b⃗ ( ∵ | a⃗ | #160;= |b⃗| = | c⃗ | = 1) = 6 2 ∑ | a⃗ ...

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Applications of Dot Product

If a⃗ , b⃗ ...

Question

If $\to a, \to b, \to c$ are unit vectors, then $| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}$ does not exceed :

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Solution

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Similar questions

\to a, \to b

\to c

{∣ ∣ \to a - \to b ∣ ∣}^{2} + {∣ ∣ \to b - \to c ∣ ∣}^{2} + {| \to c - \to a |}^{2}

\to a, \to b

\to c

{∣ ∣ \to a - \to b ∣ ∣}^{2} + {∣ ∣ \to b - \to c ∣ ∣}^{2} + {| \to c - \to a |}^{2}

\to a, \to b

\to c

| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}

\to a, \to b, \to c

{∣ ∣ \to a - 2 \to b ∣ ∣}^{2} + {∣ ∣ \to b - 2 \to c ∣ ∣}^{2} + {| \to c - 2 \to a |}^{2}

\to a, \to b, \to c

\to b, \to c

(\to a, \to b) = α, (\to a, \to c) = β

\to a \times (\to b \times \to c) = \frac{\to b + \to c}{2}

c o s (α + β) =

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