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Question

If a,b,c be three non coplanar unit vectors, c is inclined at an angle α to the plane of a and b and a and c are inclined at an angle β to b, then (a×b)×(b×c)×(c×a) is

A
12sin2αsinβ (ca)
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B
12sin2βsinα(ca)
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C
12sin2αcosβ(ca)
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D
12sin2βcosα(ca)
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Solution

The correct option is B 12sin2βsinα(ca)
(¯¯¯aׯ¯b)×(¯¯bׯ¯c)×(¯¯cׯ¯¯a)=[¯¯¯a¯¯b¯¯c]¯¯b×(¯¯cׯ¯¯a)
=[¯¯¯a¯¯b¯¯c]{(¯¯b.¯¯¯a)¯¯c(¯¯b.¯¯c)¯¯¯a} ... (1)
But [¯¯¯a¯¯b¯¯c]=|¯¯¯aׯ¯b|¯¯c|cos of angle between (¯¯¯aׯ¯b) and ¯¯c
=|¯¯¯a|¯¯b|sinβ|¯¯c| (cos of angle between the normal to the plane and the line)
=1.1.sinβ.1 (sine of angle between the plane and the line )
=sinβsinα
(¯¯¯aׯ¯b)×(¯¯bׯ¯c)×(¯¯cׯ¯¯a)=sinβsinα{1.1cosβ[¯¯c¯¯¯¯a]}
=sinβcosβsinα(¯¯c¯¯¯a)
=12sin2βsinα(¯¯c¯¯¯a)

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