If a-xi-yj-b-yi-xj- and -a-b-5- then locus of x-y is

The correct option is B C ircle a⃗×b⃗=î amp;ĵ #160; amp;k̂ x #160; amp; y #160; amp;0 y #160; #160; amp;x #160; amp ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Applications of Cross Product

If a⃗=xi⃗-y...

Question

If $\to a = x \to i - y \to j, \to b = y \to i + x \to j$ and $| \to a \times \to b | = 5$ , then locus of $(x, y)$ is

Hyperbola

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Parabola

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Ellipse

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

ircle

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

\to a = \to i - \to k

\to b = x \to i + \to j + (1 - x) \to k

\to c = y \to i + x \to j + (1 + x - y) \to k

[\to a \to b \to c]

\to a = x^i - y^j

\to b = y^i + x^j, | \to a \times \to b | = 5

(x, y)

\to a = \to i - \to k

\to b = x \to i + \to j + (1 - x) \to k

\to c = y \to i + x \to j + (1 + x - y) \to k

\to a, \to b

\to c

| \to a | = 5

∣ ∣ \to a - \to b ∣ ∣ = 8

∣ ∣ \to a + \to b ∣ ∣ = 10

∣ ∣ \to b ∣ ∣

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

Join BYJU'S Learning Program