If b- -3- -4- and a- -i- -j- then vector having the same magnitude as that of b- and parallel to a- is

The correct option is A 5 √( 2 )( i⃗ j⃗) [ a = i j #160; /√( 2 ) #160; | b #160; | =5; c = 5 /√( 2 ) #160; ( ...

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Definition of Vector

If b⃗ =3î +...

Question

If $\to b = 3^i + 4^j$ and $\to a = \to i - \to j$ , then vector having the same magnitude as that of $\to b$ and parallel to $\to a$ is

\frac{5}{\sqrt{2}} (\to i - \to j)

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\frac{5}{\sqrt{2}} (\to i + \to j)

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5 (^i -^j)

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5 (^i +^j)

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Solution

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Similar questions

\to a = \to i + \to j + \to k, \to a = 2 \to i + \to k, \to c = 2 \to i + \to j + \to k; \to d = \to i + \to j + 2 \to k

(\to a \times \to b) \times (\to c \times \to d) = [\to a \to b \to d] \to c - [\to a \to b \to c] \to d

\to a = \to i - 2 \to j - 3 \to k, \to b = 2 \to i + \to j - \to k, \to c = \to i + 3 \to j - 2 \to k

(\to a \times \to b) \times \to c

\to a = 2 \to i + \to j - 2 \to k

\to b = \to i + \to j

\to c

\to a . \to c = | \to c |

| \to c - \to a | = 2 \sqrt{2}

\to a \times \to b

\to c

30^{\circ}

∣ ∣ (\to a \times \to b) \times \to c ∣ ∣

\to r = 3 \to i + 2 \to j - 5 \to k

\to a = 2 \to i - \to j + \to k

\to b = \to i + 3 \to j - 2 \to k

\to c = - 2 \to i + \to j - 3 \to k

\to r = λ \to a + μ \to b + ν \to c

\to a = 3 \to i + 2 \to j + 6 \to k

\to b = 2 \to i + \to j + \to k

\to c = \to i - \to j + \to k

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