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Question

If DA=a, AB=b, CB=ka where k>0 X, Y are the mid points of DB and AC respectively, such that |a|=17 and XY=4, then k equal to ?

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Solution

Let D be origin DA=AD=a
A=a
AB=BA=b
B=a+b
CB=BC=ka
C=a+bka
x=a+b2, y=2a+bka2
xy=aka2=(1k2)a
(xy)=(1k2)|a|
4=(1k2)17
1k=817
k=917.

1134149_1242218_ans_a330f66910cc409e997e446c2ec04c10.jpg

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