Question

If $\overrightarrow{F}=2\hat{i}+3\hat{j}+4\hat{k}$ acts on a body and displaces it by $\overrightarrow{S}=3\hat{i}+2\hat{j}+5\hat{k}$, then the work done by the force is:

• A. $\sqrt{110}J$
• B. $20J$
• C. $32J$
• D. $64J$

Answer 1

The correct option is C $32J$

$W=\overrightarrow{F}.\overrightarrow{S}$
$=(2\hat{i}+3\hat{j}+4\hat{k}).(3\hat{i}+2\hat{j}+5\hat{k})$
$=6+6+20$
$=32J$