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Question

If OA=^i^j and OB=^j^k, then a unit vector parpendicular to the plane AOB is

A
13(^i+^j^k)
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B
13(^i+^j+^k)
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C
13(^i^j^k)
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D
12(^i+^j+^k)
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Solution

The correct option is B 13(^i+^j+^k)
V=˙OA×OB=∣ ∣ ∣^i^j^k110011∣ ∣ ∣=^i+^j+^k
V=3
^V=13(^i+^j+^k)

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