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Question

If P=^i+2^k and Q=2^i+^j2^k are two vectors, find the unit vector parallel to P×Q. Also find the vector perpendicular to P and Q of magnitude 6 units.

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Solution

Let R be the vector perpendicular to P and Q

R = P×Q

= (^i+2^k)×(2^i+^j2^k)

R=2^i+6^j+^K

so unit vector along (P×Q)

And S is a vector along R vector having magnitude 6

S=6×P×Q|P×Q|
= 6×2^i+6^j+^k41

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