If →P=^i+2^k and →Q=2^i+^j−2^k are two vectors, find the unit vector parallel to →P×→Q. Also find the vector perpendicular to P and Q of magnitude 6 units.
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Solution
Let R be the vector perpendicular to P and Q
→R = →P×→Q
= (^i+2^k)×(2^i+^j−2^k)
→R=−2^i+6^j+^K
so unit vector along (→P×→Q)
And S is a vector along R vector having magnitude 6