If r-a-b-a- r-b-a-b- a- 0-b- 0-a-b- a- is not perpendicular to b- then r-

The correct option is C a⃗+b⃗ Given, r⃗× #160;a⃗ = (a⃗× #160;b⃗) #160;and #160; r⃗ #160;× #160;b⃗ = #160;a⃗× #160;b⃗ Thus, #1 ...

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If r⃗×a⃗=b⃗...

Question

If $\to r \times \to a = \to b \times \to a; \to r \times \to b = \to a \times \to b; \to a \neq 0, \to b \neq 0, \to a \neq λ \to b; \to a$ is not perpendicular to $\to b$ , then $\to r =$

\to a - \to b

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\to a + \to b

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\to a \times \to b + \to a

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\to a \times \to b + \to b

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