If -L-0 for a rigid body- where -resultant torque L-angular momentum about a point and both are non - zero- Then

The correct option is C |L⃗| may increaseIf τ⃗×L⃗=0 this implies θ = 0 or π when θ=0 #160; ⇒L⃗ will increaseand when ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Final Velocities

If τ⃗×L⃗=0 ...

Question

If $\to τ \times \to L = 0$ for a rigid body, where $\to τ =$ resultant torque & $\to L =$ angular momentum about a point and both are non - zero. Then

\to L =

constant

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| \to L | =

constant

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| \to L |

will increase

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| \to L |

may increase

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $| \to L |$ may increase
If $\to τ \times \to L = 0$
this implies $θ = 0$ or $π$
when $θ = 0$ $\Rightarrow \to L$ will increase
and when $θ = π$ $\Rightarrow \to L$ will decrease

Suggest Corrections

Similar questions

Q. If

\to τ \times \to L = 0

for a rigid body , where

\to τ

= resultant torque &

\to L

= angular momentum about a point and both are non - zero. Then

Q. The torque

\to τ

on a body about a given point is found to be

\to A \times \to L

where

\to A

is a constant vector and

\to L

is angular momentum of the body about that point. From this it follows that

Q. The torque

\to τ

on a body about a given point is found to be equal to

\to A \times \to L

where

\to A

is a constant vector and

\to L

is the angular momentum of the body about that point. From this it follows that :

Q. The torque

τ

on a body about a given point is found to be equal to

\to A \times \to L

, where

\to A

is a constant vector and

\to L

is the angular momentum of the body about the point. From this, it follows that

τ = \frac{d \to L}{d t}

(where

L

is the angular momentum and

t

is time).
a)

\to A

is perpendicular to

\to L

at all instants of time.
b) The component of

\to L

in the direction of

\to A

does not change with time.
c) The magnitude of

\to L

does not change with time.
d)

\to L

does not change with time.

Q. The angular momentum of a particle relative to a certain O varies

\to L = \to a + \to b t^{2}

where

\to a

and

\to b

are constant vectors with

\to a

perpendicular to

\to b

. The torque

\to t

relative to the point O acting on the particle when angle between

\to τ

and

\to L

45^{o}

is:

Join BYJU'S Learning Program

If →τ×→L=0 for a rigid body, where →τ=resultant torque & →L=angular momentum about a point and both are non - zero. Then

The correct option is C |→L| may increaseIf →τ×→L=0this implies θ=0 or πwhen θ=0 ⇒→L will increaseand when θ=π ⇒→L will decrease

If $\to τ \times \to L = 0$ for a rigid body, where $\to τ =$ resultant torque & $\to L =$ angular momentum about a point and both are non - zero. Then

The correct option is C $| \to L |$ may increase
If $\to τ \times \to L = 0$
this implies $θ = 0$ or $π$
when $θ = 0$ $\Rightarrow \to L$ will increase
and when $θ = π$ $\Rightarrow \to L$ will decrease