If x- and y- are unit vectors inclined at an angle 600 so that x-y-a- and x-y-b- then x- can be expressed as

The correct option is B a⃗2⃗+13(a⃗×b⃗) x⃗×y⃗=x⃗×a⃗ b⃗=x⃗×a⃗ a⃗×b⃗=a⃗×x⃗×a⃗ (Vector product formula) a⃗×b⃗=a^2x⃗ (a⃗.x⃗)a⃗ ———(1) |x ...

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Condition for Coplanarity of Four Points

If x⃗ and ...

Question

If $\to x$ and $\to y$ are unit vectors inclined at an angle $60^{0}$ so that $\to x + \to y = \to a$ and $\to x \times \to y = \to b$ , then $\to x$ can be expressed as

\to \frac{a}{2} + \frac{1}{3} (\to a \times \to b)

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\to \frac{a}{2} - \frac{1}{3} (\to a \times \to b)

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\to \frac{a}{3} + \frac{1}{2} (\to a \times \to b)

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\to a

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\to x \times \to y = \to a, \to y \times \to z = \to b, \to x \cdot \to b = γ, \to x \cdot \to y = 1

\to y \cdot \to z = 1

\to x

\to x

\to x, \to y

\to z,

\sqrt{2},

60^{\circ}

\to x \times (\to y \times \to z) = \to a, \to y \times (\to z \times \to x) = \to b

\to x \times \to y = \to c .

\to a \times (\to b \times \to c) + \to b \times (\to c \times \to a) + \to c \times (\to a \times \to b) = \to x \times \to y

\to x, \to y, \to z

\to x + \to y + \to z = \to a

(\to x \times \to y) \times \to z = \to b

\to a \cdot \to x = \frac{3}{2}, \to a \cdot \to y = \frac{7}{4}

| \to a | = 2,

\to x \times \to y = \to a, \to y \times \to z = \to b, \to x \cdot \to b = γ, \to x \cdot \to y = 1

\to y \cdot \to z = 1

\to y

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