MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Real Valued Functions

If x⃗ satis...

Question

If $\to x$ satisfying the conditions $\to b$ . $\to x$ = $β$ & $\to b$ x $\to x$ = $\to a$ is $\to x = \frac{(β^{2} - 12) \to b}{{∣ ∣ \to b ∣ ∣}^{2}} + \frac{\to a \times \to b}{{∣ ∣ \to b ∣ ∣}^{2}}$ then $β$ can be

Open in App

Solution

$\to b . \to x = β$
$\to x = \frac{(β^{2} - 12) \to b}{| \to b |^{2}} + \frac{\to a \times \to b}{| \to b |^{2}}$
$\to b . \to x = β^{2} - 12 = β ⟹ β^{2} - β - 12 = 0 ⟹ β = 4, - 3$

Suggest Corrections

thumbs-up

0

Similar questions

\to a

\to b

be two non-zero perpendicular vectors. If a vector

\to x

satisfying the equation

\to x

\to b

\to a

\to x

β \to b - \frac{1}{{∣ ∣ \to b ∣ ∣}^{2}}

\to a

\to b

β

\to a \times (\to b \times \to c) + (\to a . \to b) \to b = (4 - 2 β - sin α) \to b + (β^{2} - 1) \to c

(\to c . \to c) \to a = \to c

\to b

\to c

are non-collinear, then the value of scalars

α

β

\to x \times \to b = \to c \times \to b

\to x ⊥ \to a

\to x

\to a + \to b + \to c = 0, | \to a | = 3, ∣ ∣ \to b ∣ ∣ = 5, | \to c | = 7

, then the angle between

\to a

\to b

\to a + \to b + \to c = 0, | \to a | = 3, ∣ ∣ \to b ∣ ∣ = 5

| \to c | = 7

, then find the angle between

\to a

\to b

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Real Valued Functions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Real Valued Functions

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon