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Question

If vector a is collinear with vector b=3^i+6^j+6^k and ab=27. Then a is equal to

A
^i+2^j+2^k
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B
2^i+^j+^k
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C
^i2^j2^k
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D
2^i2^j+2^k
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Solution

The correct option is A ^i+2^j+2^k
Given,a and b are collinear.
Hence, a=kb
ab=27k(bb)=27,(b=3^i+6^j+6^k)(9+36+36)k=27k=13
So, a=^i+2^j+2^k

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