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Question

If vector x satisfying x×a+(xb)c=d is given by x=λa+a×a×(d×c)(ac)|a|2, then the value of λ=

A
(ab)|a|2
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B
(ax)|a|2
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C
(ac)|a|2
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D
(ad)|a|2
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Solution

The correct option is B (ax)|a|2
Given: x×a+(xb)c=d
{x×a+(xb)c}×c=d×c(x×a)×c+(xb)(c×c)=d×c(xc)a(ac)x=d×ca×{(xc)a(ac)x}=a×{d×c}(ac)(a×x)=a×{d×c}x×a=a×(d×c)aca×(x×a)=a×a×(d×c)ac(aa)x(ax)a=a×a×(d×c)acx=(ax)a|a|2+a×a×(d×c)(ac)|a|2(i)
Comparing (i) with x=λa+a×a×(d×c)(ac)|a|2,
λ=(ax)|a|2

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