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Question

If vector AB=2^i^j+^k and OB=3^i4^j+4^k find the position vector OA

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Solution

AB=2^i^j+^k=ba….(1);
OA=3^i4^j+4^k=a0 …………(2)
Equation (2)- Equation (1)
a0=OA=^i3^j+3^k.

1214471_1396112_ans_7d999d658a50437fa4e878969fc7bc0b.jpg

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