If vectors A- B and C have magnitudes 5- 12 and 13 units and A- B- C- then the angle between B and C is

Given $\to A + \to B = \to C$ and the magnitudes of vectors $\to A$ , $\to B$ and $\to C$ are respectively 12, 5 and 13 units. The angle between $\to A$ and $\to B$ is

Q. If the magnitude of vectors

\to A

\to B

and

\to C

are 12, 5 and 13, respectively and

\to C = \to A + \to B

, then the angle between the vectors

\to A

and

\to B

Q. If the magnitude of vectors

\to A, \to B

and

\to C

are

12, 5

and

13

units, respectively, and

\to A + \to B = \to C

, the angle between vectors

\to A a n d \to B

is:

The magnitude of vector $\to A, \to B$ and $\to C$ are respectively 12, 5 and 13 units and $\to A + \to B = \to C$ then the angle between $\to A$ and $\to B$ is

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If vectors →A,→B and →C have magnitudes 5,12 and 13 units and →A+→B=→C, then the angle between →B and →C is

The correct option is B cos−11213As →A+→B=→C ∴→A=→C−→B ⇒|→A|2=|→C−→B|2 ⇒|→A|2=|→C|2+|→B|2−2|→C||→B| cos θ ⇒ cos θ=132+122−522×13×12=288312=1213 ⇒ θ=cos−11213 Also, sinθ=√1−cos2θ=√1−(1213)2=513 ⇒θ=sin−1513

If vectors $\to A, \to B$ and $\to C$ have magnitudes $5, 12$ and $13$ units and $\to A + \to B = \to C,$ then the angle between $\to B$ and $\to C$ is