You visited us 1 times! Enjoying our articles? Unlock Full Access!

Parabola

If vectors ...

Question

If vectors $\to a$ and $\to b$ are two adjacent sides of a parallelogram then the vector representing the altitude of the parallelogram which is perpendicular to $\to a$ is

\to b + \frac{\to b \times \to a}{| \to a |^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\to a . \to b}{| \to b |^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to b - \frac{\to a . \to b}{| \to a |^{2}} \to a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{\to a \times (\to b \times \to a)}{| \to b |^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\to a . \to b}{| \to a |^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\to b - \frac{\to a . \to b}{| \to a |^{2}} \to a$
Let $\to O D = t \to a$ where $t$ is any constant
$∴ \to D B = \to b - t \to a$
$∴ (\to b - t \to a) . \to a = 0$
$t = \frac{\to b . \to a}{| \to a |^{2}}$

$∴ \to D B = \to b - \frac{(\to b . \to a) \to a}{| \to a |^{2}}$

Suggest Corrections

Similar questions

| \to a + \to b | = | \to a - \to b |

(\to a, \to b) = \frac{π}{2}

\to a, \to b, \to a + \to b

(\to a, \to b) = \frac{2 π}{3}

\to a

\to b

| \to a \times \to b |^{2} = | \to a |^{2} | \to b |^{2} - | \to a . \to b |^{2}

\to a

\to b

\frac{{∣ ∣ \to a + \to b ∣ ∣}^{2} - {∣ ∣ \to a - \to b ∣ ∣}^{2}}{{∣ ∣ \to a + \to b ∣ ∣}^{2} + {∣ ∣ \to a - \to b ∣ ∣}^{2}}

| \to a | \to b + | \to b | \to a

| \to a | \to b - | \to b | \to a

\to a

\to b

| \to a | \to b + | \to b | \to a

| \to a | \to b - | \to b | \to a

\to a

\to b

Join BYJU'S Learning Program