If velocities of $5$ molecules of certain gas are $- 7, 5, 4, - 3$ and $1 m / s e c$ respectively then mean speed of molecules is ( $m / s e c$ )

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4

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\sqrt{20}

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Solution

The correct option is B $4$
Mean speed will be just the average of their $s p e e d s$ not the velocity so don't consider the negative sign
because it just denotes direction which we don't need while dealing with speed.
So average speed will be $v = \frac{7 + 5 + 4 + 3 + 1}{5} = 4 m / s$

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If velocities of 5 molecules of certain gas are −7,5,4,−3 and 1 m/sec respectively then mean speed of molecules is (m/sec)

The correct option is B 4Mean speed will be just the average of their speeds not the velocity so don't consider the negative sign because it just denotes direction which we don't need while dealing with speed.So average speed will be v=7+5+4+3+15=4m/s

If velocities of $5$ molecules of certain gas are $- 7, 5, 4, - 3$ and $1 m / s e c$ respectively then mean speed of molecules is ( $m / s e c$ )

The correct option is B $4$
Mean speed will be just the average of their $s p e e d s$ not the velocity so don't consider the negative sign
because it just denotes direction which we don't need while dealing with speed.
So average speed will be $v = \frac{7 + 5 + 4 + 3 + 1}{5} = 4 m / s$