Question

If velocity of a particle depends on time 't' as $v=t^2-t-6$ then find the time for which velocity remained negative

• A. 5 second
• B. 3 second
• C. 2 second
• D. 1 second

Answer 1

The correct option is B 3 second

The velocity is given as $v=t^2-t-6$

For velocity to be negative, $v<0$

Or $t^2-t-6<0$

Or $(t+2)(t-3)<0$

(Since time cannot be negative, so $(t+2)$ is always positive)

Or $t-3<0$

$⟹t<3seconds$

Thus, up to $t=3s$, the velocity remains negative.