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Standard XII

Mathematics

Average Rate of Change

If velocity o...

Question

If velocity of a particle is given by $v = 2 t - 1$ , then find the acceleration of particle at $t = 2 s$ .

2 m / s^{2}

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4 m / s^{2}

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8 m / s^{2}

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6 m / s^{2}

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Solution

The correct option is A $2 m / s^{2}$
Given,
$v = 2 t - 1$
$\Rightarrow a = \frac{d v}{d t} = \frac{d}{d t} (2 t - 1) = 2$
$∴ a = 2 m / s^{2}$

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If velocity of a particle is given by v=2t−1, then find the acceleration of particle at t=2 s.

The correct option is A 2 m/s2Given, v=2t−1 ⇒a=dvdt=ddt(2t−1)=2 ∴a=2 m/s2

If velocity of a particle is given by $v = 2 t - 1$ , then find the acceleration of particle at $t = 2 s$ .

The correct option is A $2 m / s^{2}$
Given,
$v = 2 t - 1$
$\Rightarrow a = \frac{d v}{d t} = \frac{d}{d t} (2 t - 1) = 2$
$∴ a = 2 m / s^{2}$