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Question

If velocity of light c, Planck's constant h and gravitational constant G are taken as fundamental quantities then the dimensions of length will be:

A
chG
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B
hGc5
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C
hGc3
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D
hc3G
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Solution

The correct option is C hGc3
Let lcxhyGz;l=kcxhyGz
where k is a dimensionless constant and x, y and z are the exponents.
Equating dimensions on both sides, we get
[M0LT0]=[LT1]x[ML2T1]y[M1L3T2]z
=[MyzLx+2y+3zTxy2z]
Applying the principle of homogeneity of dimensions, we get
yz=0 ....(i)
x+2y+3z=1 ....(ii)
xy2z=0 ...(iii)
On solving Eqs. (i), (ii) and (iii), we get
x=32,y=12z=12l=hGc3

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