If |z|=1 and z1−z3z2−z3=z−iz+i then z1,z2,z3 will be vertices of a
A
acute triangle
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B
obtuse triangle
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C
right triangle
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Solution
The correct option is C right triangle As |z|=1 lies on circle, so I and -I are extremities of this circle. So, arg (z−iz+i) = ±π2⇒z−iz+i is purely imaginary ⇒z1,z2,z3 represents vertices of right angled triangle