Question

If vinegar has a pH of $\frac{142}{37}$, which one of the following decimal values (round off to 2 decimal places) is closest to this requirement?

• A. 3.82
• B. 3.84
• C. 3.85
• D. 3.87

Answer 1

The correct option is B 3.84

Given: 142 ÷ 37

Using the long division, we have:

$$\begin{array}{c}3.837\\ 37142\\ -\underset{–}{111}2\\ 310\\ -\underset{–}{296}\\ 140\\ -\underset{–}{111}\\ 290\\ -\underset{–}{259}\\ 31\end{array}$$

Therefore,
142 ÷ 37 = 3.837837.....
Rounding off to 2 decimal places,
3.3.837837.....= 3.84 (Since the digit at thousandths place is > 5.)