wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

if w,x,y,z∈ R+ and 256xyzw≥slant{(w+x+y+z)}^4and 3w+5x+7y+9z=24,then roots of equation (w+x)t^2+yzt+\sqrt{x+y+w+z}=0 are

Join BYJU'S Learning Program
CrossIcon