If war breaks out on the average once in 25 years, the probability that in 50 years at a stretch, there will be no war is

(\frac{24}{25})^{50}

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(\frac{1}{25})^{50}

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(\frac{1}{24})^{50}

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(\frac{23}{24})^{50}

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Solution

The correct option is A $(\frac{24}{25})^{50}$
War happens one times in a year so, probability of happening war $P = \frac{1}{25}$
Probability that in 50 years at a stretch, there will be no war is $= (1 - P)^{50} = (\frac{24}{25})^{50}$

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If war breaks out on the average once in 25 years, the probability that in 50 years at a stretch, there will be no war is

The correct option is A (2425)50War happens one times in a year so, probability of happening war P=125Probability that in 50 years at a stretch, there will be no war is =(1−P)50=(2425)50

The correct option is A $(\frac{24}{25})^{50}$
War happens one times in a year so, probability of happening war $P = \frac{1}{25}$
Probability that in 50 years at a stretch, there will be no war is $= (1 - P)^{50} = (\frac{24}{25})^{50}$