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Depression in Freezing Point

If water vapo...

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If water vapour is assumed to be a perfect gas, molar enthalpy change for vaporization of 1 mol of water at 1 bar and 100 degree Celsius is 41kJ/mol. Calculate the internal energy change, when 1 mol of water is vaporised at 1 bar pressure and 100 degree Celsius.

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Solution

$T h e c h a n g e o f l i q u i d w a t e r t o v a p o u r i s r e p r e s e n t e d a s H_{2} O_{(l)} \to H_{2} O_{(g)} T h e r e l a t i o n b e t w e e n c h a n g e i n e n t h a l p y a n d i n t e r n a l e n e r g y i s g i v e n a s ∆ H = ∆ E + R T ∆ n ∆ E = ∆ H - R T ∆ n = 41 - 8.314 \times 10^{- 3} \times 373 \times 1 = 41 - 3.10 = 37.90 k J / m o l$

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If water vapour is assumed to be a perfect gas, molar enthalpy change for vapourization of 1 mol of water at 1 bar and

100^{0} C

41 k J . {m o l}^{- 1}

. Calculate the internal energy change, when 1 mol of water is vaporized at 1 bar pressure and

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