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Question

If we add 1*10-8 of HCl into pure water in the following reaction:
HCl (aq) + H2O (l) to give H3O+ (aq) + Cl- (aq)
and assuming that volume doesn't change when HCl is added, why is H3O+ = HCl = 10-8? Shouldn't it be H3O+ + HCl = 10-8 because HCl is dissolved with water?

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Solution

Here its given that HCl is added to pure water.
Pure water is neutral, its pH is 7. so it wont affect the concentration of H3O+ ions.
Now
Given reaction is
HCl (aq) + H2O (l) ---> H3O+ (aq) + Cl- (aq)
Here we see that molar ratio of HCl: H3O+ = 1:1
this means concentration of HCl = concentration of H3O+

that is why when 1 x 10^-8 M HCl is added to pure water, the [H3O+] = [HCl] = 1x 10^-8
[HCl] = [H3O+]




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