Question

If we allow current to pass through the given setup for some time, which of the following can be observed?

• A. Copper gets deposited into the electrode connected to the positive terminal of the battery.
• B. Copper gets dissolved into the solution from the electrode connected to the negative terminal.
• C. Copper gets deposited into the electrode connected to the negative terminal of the battery.
• D. Copper residues settle in the electrolyte.

Answer 1

The correct option is C Copper gets deposited into the electrode connected to the negative terminal of the battery.

When electric current is passed through the copper sulphate solution, copper sulphate solution dissociates into $C{u}^{2+}$ and $S{O}_2{}^{2-}$ ions. The $C{u}^{2+}$ gets drawn to the electrode connected to the negative terminal of the battery and gets deposited into it.