If we calculate the oxidation state of oxygen in Na2O2, why is it + 1 ?

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The oxidation state of oxygen in $K O_{3}$ , $N a_{2} O_{2}$ are respectively :

Why in the case of H₂O₂the oxidation state of Oxygen is -1?

When we have to take the oxidation state for oxygen as -1?

The oxidation state of oxygen in $K O_{3}$ , $N a_{2} O_{2}$ are respectively :

O F_{2}, O_{2}, N a_{2} O_{2}

C H_{3} C O O H

K O_{3}

N a_{2} O_{2}

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