If we have a function fx- x 2 -6x- x- 2 2x-1- x-2 f3-

The correct option is A 5 Clearly for x=3 f(x)=2x=2×3 1=5 ...

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Definition of Functions

If we have a ...

Question

If we have a function
$f (x) = {\begin{matrix} x^{2} - 6 x, x \leq 2 2 x - 1, x > 2 \end{matrix}$
$f (3) =$

- 9

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5

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8

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6

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Not defined

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If f:N $\to$ N be a function defined by f(x) = $x^{2}$ + x, then find f(-2).f(2) + f(3).

f

f (x) = {\begin{matrix} 2 x + 4, x \leq 2 2 x - 1, x > 2 \end{matrix}

f (0) + f (2) + f (4)

f (x) = (\begin{matrix} x^{2} - 1, if 0 < x < 2 2 x + 3, if 2 \leq x < 3 \end{matrix}

lim x \to 2^{-} f (x) and lim x \to 2^{+} f (x)

f (x)

f (x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{x^{2} - 1}{x^{2} - 2 | x - 1 | - 1}, & x \neq 1 \frac{1}{2}, & x = 1 \end{matrix}

x = 1

f : [1, 6) \to R

f (x) =

⎧ ⎨ ⎩ \begin{matrix} 1 + x, 1 \leq x < 2 2 x - 1, 2 \leq x < 4 3 x^{2} - 10, 4 \leq x < 6 \end{matrix}

[1, 6) = {x \in R : 1 \leq x < 6}

f (5)

f (3)

f (1)

f (2) - f (4)

2 f (5) - 3 f (1)

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