The correct option is C 1500
1 mole of CH3OH contains 4 moles of H atoms.
So, we can say that 4 moles of H-atoms are present in 1 mole of CH3OH.
Again, 6.022×1023 H-atoms = 1 mole of H-atoms
Therefore, 6000 H - atoms =60006.022 × 1023 moles of H-atoms
Hence, the number of CH3OH molecules present in the sample
=60006.022 × 1023×14×6.022×1023=1500